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Unformatted text preview: Problem 2 (50). A recuperated (regenerated) Brayton cycle system is shown in the figure below. The following data are provided: T 1 = 300K p 1 =1 atm T 4 =1200K p 2 =4 atm c =80% T =85% C p =1.005 kJ/kgK for the cold section (States 1 to 3); C p =1.100 kJ/kgK for the hot section (States 3 to 6); air treated as thermally perfect a) For the recuperated cycle shown, find the cycle efficiency and specific work. Treat the Recuperator as ideal, which means that T 3 =T 5 and T 6 =T 2 . b) Without the Recuperator, State 3 is the same as State 2, State 6 is the same as State 5. For that case, find the cycle efficiency and specific work. Comp Turb Combustor Recuperator 1 2 3 4 5 6...
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 Spring '08
 Sherif

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