{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Q2Sols - 1 QUIZ#2SOLUTIONS Page653Problem2 A= 2 2 1 2 e 2 2...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
QUIZ #2 – SOLUTIONS 1) Page 653 – Problem 2 A = 1 2 e θ 2 ( ) 2 d θ π 2 π = 1 2 e θ d θ π 2 π = 1 2 e θ π 2 π = 1 2 e 2 π e π ( ) 256.175 2) Page 653 – Problem 6 A = 1 2 1 + cos θ ( ) 2 d θ 0 π = 1 2 1 + 2cos θ + cos 2 θ ( ) d θ 0 π = 1 2 1 + 2cos θ + 1 2 1 + cos2 θ ( ) d θ 0 π
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern