Q2Sols - 1 QUIZ#2 – SOLUTIONS Page 653 – Problem 2 A= 2π π 2 1 θ2 e 2 2 1 dθ = 2 2π ∫e θ dθ = π 1 θ 2π 1 2π e ⎤π = e − eπ

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Unformatted text preview: 1) QUIZ #2 – SOLUTIONS Page 653 – Problem 2 A= 2π ∫ π 2) () 1 θ2 e 2 2 1 dθ = 2 2π ∫e θ dθ = π ( ) 1 θ 2π 1 2π e ⎤π = e − eπ ≈ 256.175 2⎦ 2 Page 653 – Problem 6 π π ( ) 1 1 2 A = ∫ (1 + cos θ ) dθ = ∫ 1 + 2 cos θ + cos 2 θ dθ = 2 20 0 π π 1⎛ 1 13 1 ⎞ ⎜ 1 + 2 cos θ + (1 + cos 2θ )⎟ dθ = ∫ + 2 cos θ + cos 2θ dθ = ⎠ 2 ∫⎝ 2 202 2 0 π 1 ⎡3 1 3π ⎤ ⎢ 2 θ + 2 sin θ + 4 sin 2θ ⎥ = 4 2⎣ ⎦0 ...
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This note was uploaded on 09/06/2011 for the course MATH 1c taught by Professor Garrison during the Spring '11 term at DeAnza College.

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