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Experiment 12 Chemical Equilibrium and Beer's Law

Experiment 12 Chemical Equilibrium and Beer's Law -...

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Experiment 12 Chemical Equilibrium and Beer’s Law Sidney Sherrill Robert Barrentine November 23, 2010 I certify this work is my own. Sidney Sherrill
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Data Part A. Determining  b from Beer’s Law Plot ε ID mL [Fe ( SCN ) 2+ ] Abs. Fe 3+ SCN HNO Total 1 1.0 5.0 4.0 1 1E-5 0.10 1 2 2.0 5.0 3.0 1 2E-5 0.21 2 3 3.0 5.0 2.0 1 3E-5 0.31 1 4 4.0 5.0 1.0 1 4E-5 0.42 8 5 5.0 5.0 0.0 1 5E-5 0.52 1 [Fe(NO 3 ) 3 Stock  (M) 0.00 25 [Fe(NO 3 ) 3 Diluted  (M) 0.00 01 [KSCN]  Stock  (M) 0.00 25 [HNO 3 Stock  (M) 0.1 Sample Calculations: = m1v1 m2v2 1. [F + e3 ] working:  . (. )= (. ) 0025 M FeNO3 004 L m2 1 L =. × - m2 0001 or 1 10 4 2. [F + e3 ] test tube 1: × - = ( ) 1 10 41 mL m2 10 mL =. m2 001 3. = A εbc = εb Ac = εb 10560
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4. : ε   5. = ε1 cm 10560 6. = ε 10560 7. 8. Part B: Determining the Equilibrium Constant, k 9 . I 10. mL 1 1 . A 12. (M) 1 3. K 1 5 . F 1 6 . S 17 . H 1 8 . T 1 9 . 20. [ F e 3+ ini tia l 21. [SC N - initial 22. [F e( SC N) 2+ ] 23. [ F e 3 + ]   e q . 24. [ S C N - eq. 25 . 2 6 . 6 2 7 . 1 2 8 . 1 29 . 5. 3 0 . 7 3 1 . 0 32. 3 . 5 7 E - 0 4 33. 3.5 7E- 04 34. 6. 61 E- 05 35. 2 . 9 1 E - 0 4 36. 2 . 9 1 E - 0 4 3 7. 7. 3 8 . 7 3 9 . 1 4 0 . 1 41 . 4. 4 2 . 7 4 3 . 0 44. 3 . 5 7 E - 0 4 45. 5.3 6E- 04 46. 5. 61 E- 05 47. 3 . 0 1 E - 0 4 48. 4 . 8 0 E - 0 4 4 9. 3. 5 0 . 8 5 1 . 1 5 2 . 2 53 . 5. 5 4 .
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