M06 Problems

M06 Problems - small percent differences between my three...

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Fi t y-variable Relationship Coefficient Units of coefficien t Power of R m Value of Coefficient Mass of Planet (kg) Percentag e Differenc e 1 Acceleration , a a = (GM p )/ R m ² GM p m 3 /s² -2 6.993x10^1 5 1.048x10^26 0 2 Speed, v v=( GM p / R m )^.5 (GM p )^.5 m 1.5 /s -0.5 8.365x10^7 1.049x10^26 0.10% 3 Period, T T=2*pi* R m ^1.5/ ( GM p )^.5 (2*pi)/ ( GM p )^.5 s/ m 1.5 1.5 7.615x10^-8 1.021x10^26 2.58% Moon Radius (m) Period (s) Red 4.80 x 10 7 25200 Green 6.20 x 10 7 35800 Black 1.17x 10 8 97000 Orange 3.54 x 10 8 507200 13. In this experiment, I took the equations for acceleration, speed, and period and the moons which all involved G, mass, and radius to find the mass of the planet and then saw that I had very
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Unformatted text preview: small percent differences between my three results. 14. I found the mass of the planet by using the relationship between speed of the moons and the mass of the planet. The experimental velocity found from the animation was the time it took to complete a full rotation divided by the circumference which is radius times 2pi. When I fit this on Logger Pro, I obtained a coefficient that was supposed to be equal to (GM p / R m )^.5. So squaring the coefficient and then multiplying by R m and then dividing by G gave me M p....
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M06 Problems - small percent differences between my three...

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