L11 Part A - negative side of the resistor is the side...

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L11 Part A Resistance = 982 ohms No. of batteries Pot. Diff. V CB (V) Current, I (mA) 1 1.389 1.286 2 2.84 2.88 3 4.32 4.28 4 5.78 5.83 3. I set up the circuit by attaching 2 alligator clips to the resistor. Next, I attached one end of the alligator clip to the positive end of the battery and one end to the negative end of the battery. Then I connected the two ends to a resistor, to complete the circuit. Next, I attached a black alligator clip to the negative probe of the multimeter and a red alligator clip to the positive probe of the multimeter. I attached the red alligator clip to the positive side of the resistor and the black alligator clip to the negative side of the resistor. The
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Unformatted text preview: negative side of the resistor is the side where the negative end of the battery is connected to the resistor and vice versa for the positive side. Then I set my multimeter to Voltage and turned on my multimeter to record the potential difference. To record the current, I turned off my multimeter, and switched the red probe in the red socket to the white socket in the multimeter. Then I set my multimeter to Amperes and recorded the current. I repeated this for 1, 2, 3, and 4 batteries....
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This note was uploaded on 09/07/2011 for the course PHYSICS 101 taught by Professor Graham during the Spring '11 term at UNC.

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