{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

physics + circular motion solution

# physics + circular motion solution - PHYSICS Solution...

This preview shows pages 1–4. Sign up to view the full content.

PHYSICS + Solution --- Circular Motion Definition: Angular velocity, ϖ is rate of change of angular displacement. dt d θ ϖ = Equations: f π ϖ 2 = Relationship between v, r, ϖ and a ϖ r v = ϖ ϖ v r r v a = = = 2 2 1. ANS: B For particle moving in a horizontal circle with constant angular velocity, the kinetic energy is constant (scalar) but linear momentum varies. (vector, p = m v ) 2. ANS: C The string becomes inclined to the vertical so that there will be a horizontal component of the tension to provide for the centripetal acceleration towards the centre. 3. ANS: C v v r ∆θ centreof circular arc

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
4. ANS: E N mr T Tension 6 . 1 ) 0 . 4 )( 5 . 0 )( 20 . 0 ( , 2 2 = = = ϖ 5. (i) the angular speed 1 0 . 2 0 . 6 12 - = = = = s rad r v r v ϖ ϖ (ii) the force towards the centre. N r mv F 96 0 . 6 ) 12 )( 0 . 4 ( 2 2 = = = 6. 4.0 m θ to centre of circle θ mg T (i) the tension in the string N T T N r mv T N mg T 116 ) 5 . 62 ( ) 1 . 98 ( ) cos (sin 5 . 62 0 . 4 ) 0 . 5 ( 10 sin 1 . 98 ) 81 . 9 )( 10 ( cos 2 2 2 2 2 2 2 = + = + = = = = = = θ θ θ θ
(ii) the angle of inclination of the string to the vertical.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 5

physics + circular motion solution - PHYSICS Solution...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online