Prob3_75c 15

Prob3_75c 15 - 1 0; 0 1 0 0 0 ; 0 0 1 0 1; 0 0 0 -1.5 0; 0...

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9/7/11 The mass center of the 30-kg door is in the center of the panel. If the weight of the door is supported entirely by the lower hinge A, calculate the magnitude of the total force supported by the hinge at B. 3/7 5 x y W =(30) (9.81) =294.3 N A x A y B x 1.5 m 0.9 m y z A z B z A y W 0.36 m N
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9/7/11 Full solution (with MATLAB) x(1) Ax x(2) Ay x(3) Az x(4) Bx x(5) Bz >> C = [ 1 0 0
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Unformatted text preview: 1 0; 0 1 0 0 0 ; 0 0 1 0 1; 0 0 0 -1.5 0; 0 0 0 0 -1.5] C = 1.0000 0 0 1.0000 0 1.0000 0 0 0 0 1.0000 0 1.0000 0 0 0 -1.5000 >> C\b ans = 176.6000 294.3000 70.6000-176.6000-70.6000 >> B=sqrt(ans(4)^2 +ans(5)^2) B = 190.1892 >> b=[ 0 294.3 0 264.9 105.9]' b = 294.3000 264.9000 105.9000...
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This note was uploaded on 09/07/2011 for the course EM 274 taught by Professor Boylan during the Fall '08 term at Iowa State.

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Prob3_75c 15 - 1 0; 0 1 0 0 0 ; 0 0 1 0 1; 0 0 0 -1.5 0; 0...

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