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α
30
o
M cans, each of weight W
Determine the maximum number of cans that can be stacked on the
smooth surfaces shown as a function of the angle
α
of the left hand
surface before the stack loses equilibrium and the lowest can is
kicked out. Let
α
range from 0o to 55o
1
2
M
3
inclined axes, limits on
equilibrium
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View Full Document 30
α
M
1
2
M1 cans
W
W
W
F
x
30
o
N1
60 
α
F
30
o
W
N2
y
α
function M =cans(a)
arg = (60 a)*pi/180;
M = floor(sqrt(3)./tan(arg));
N1 = 0
when
M must be an integer so
need to round values down
to nearest integer
we can evaluate and plot this easily in MATLAB. First we define and save
a function called cans:
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View Full Document >> a =linspace(0, 55, 1000);
% the angle alpha in degrees
>> m=cans(a);
>> plot(a, m)
0
1
0
2
0
3
0
4
0
5
0
6
0
0
2
4
6
8
1
0
1
2
1
4
1
6
1
8
2
0
α
M
then we plot the number of cans versus angle
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This note was uploaded on 09/07/2011 for the course EM 274 taught by Professor Boylan during the Fall '08 term at Iowa State.
 Fall '08
 Boylan

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