CH25 - Ch 25 Questions 1. Electric potential energy is how...

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Unformatted text preview: Ch 25 Questions 1. Electric potential energy is how much work it takes to assemble a system of charges by moving them to or from a reference point (usually infinity). The work is due to the coulomb force exerted on a charged particle in an electric field and the distance it has to be moved (work = force x distance). The electric field is a result of the electric potential created by the charges of the system. 2. If a negative charge is moving in the same direction as an electric field, then it is moving in the opposite direction of the force it is experiencing. Thus its potential energy is increasing. Electric fields ‘point downhill’ ie from high to low potential, thus the charge is moving to lower potential. 5. Electric field always points in the direction of the greatest change in potential. Potential does not change along equipotential lines. The equation E = — del V shows that the magnitude of the components of the electric field are proportional to the rate of change in the direction of each component. 6. The equipotential surfaces for an infinite line are concentric cylinders centered around the line. The equipotential surfaces for a sphere are concentric spheres centered around the sphere. 7. Charges are free to move within a conductor. If the potential varied throughout the conductor there would be an electric field, and hence a force acting on the charges, causing them to move. Remember that static means nothing is moving. 8. No, it just implies that the potential is constant. Remember that the electric field is the rate of change of the potential. 26.18 o _ a (if X tlgy / g 1 gag. , E20 :— Lf + 2w X {X‘QMJ X 3"” x ~— gm 15H u: «fag; rep “I! L a ({6 WW ‘10??le a, J - W“ [1-21..z..ri_fl g," 3a A 1 9+ a .497 +17“) 1% L 3% :: ~3Jn93 25 37 WM: ave-bx CV” [00V b: firm/4‘“ a) is lice-’96“ QT Fol/1T A 3)) “LL {Dora/\Tm‘ lroI-os by *lV My lam "'7’"; low .0; 7‘17}; [5 J’Vj’f Liz. a fflWg/M/Umr fl”? 5‘ aé ' fl )- ’ _, “a /, /9‘ 991 ,_ v». : 7 ., » p “(V/CW; /" fi L" {fit/fl”? O, ,I‘; I". "HIE/EA C“... h? X i F X A J l ‘15“ /J,_ A V” ‘ é.» 154 :4" til-fl: €00? ads 9'6 ’ z, ‘4 “" " d A m \-- f I": :1 :" d “I ' Z ‘— j r A AU ,- g—4 i/ g: g Q .X : L r a F; 5mm Qifiza’rfostm’f, c i‘CmQS care C0-4WVafr/‘f/ fag? fcnrao+hf My 55 w" “Urea? {’3 5 ’74 1 ,rfrwa'i'é’ Kathi/“927 (I? 3 C A :A’LM 9 _ _ V I - L (E! _ i-m V a“ ’1‘ — A U V; / gfl : f D) 3 m J’ , ,. 15¢ J _b A ,ch ’La'. 5 {1/12 gay c'J (975/ j/ 1%.. F : D If _: g. “I? Eff \ , I, 9 \ E 3 Cr) .. V / A 4 [1 x 399 no MM; i I ’ynq . :3: / .4 a 5‘ .i 7 'E Z V _; ka i an “M” Q mafia: EH; VF ‘Zv X \ , v: ’3 0:: K ‘J -. Kg. fl ‘7},— I“ f- ..K— .2' (a UOM “D”? "1 has uni‘fs 0F 7:;- M L ' X o] W: X+oj L 1 15933”, X V ‘1 f I : WFJ 5+1 Ckxiclw : w {:5- Am A w W L+A L+d : kecx W/J -— Jfl’lW/J : kick (L “9f fights») kol \/«- kg% 5 V _ I‘D—KIC- r. g: 7.5xIOV Jaw]: ),5x 7 3797(“73/1‘ Q ~ 1 - rr) 3 N: : lBKIO'h'TC IBEX“) algal" n a" monxo“’¢. {fwiifiam OLLUFS Why/0 ’5}: BURN” (Fro-:jzzm V: 900 r. V r T“ :2 .lOOm iEl yr (b "’ ‘l kg 3 Pg ...
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This note was uploaded on 09/08/2011 for the course PHYS 142 taught by Professor Staff during the Summer '08 term at Maryland.

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CH25 - Ch 25 Questions 1. Electric potential energy is how...

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