Hwk1solnCorrection

Hwk1solnCorrection - v max by frequency times amplitude v...

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Hwk 1 Solutions PHYS 142 Summer ’09 Dr. Jenkins CORRECTION Problem 23.10 For the particle undergoing harmonic oscillation: d 2 x dt 2 = - 16 kqQ md 3 · x with: ω 2 = 16 kqQ md 3 T = π 2 s md 3 kqQ (b) Velocity at the origin is maximum; We can get
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Unformatted text preview: v max by frequency times amplitude: v max = ω x max = r 16 kqQ md 3 · a = 4 a r kqQ md 3 1...
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