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Unformatted text preview: Discussion: In this lab biphenyl was reacted with t-butyl chloride and a catalyst AlCl 3 . Essentially, the t-butyl was attached to the aromatic ring in the reaction. To find out where the t- butyl group(s) attached, NMR spectroscopy was needed. In the proton NMR only three different protons were observed. Two groups of protons coupled with each other with a coupling constant of 8.35Hz. The coupling groups had a chemical shift of protons on aromatic rings. The other proton group had a chemical shift of ordinary primary/secondary protons. By looking at the C-13 NMR there are six different carbon groups: four aromatic/alkene, a secondary/primary carbon, and a tertiary /quaternary carbon. There were nine primary/secondary protons for each two aromatic protons. From here, basically guess-and-check was applied. Since there are so few different kinds of carbons and protons, I predicted that there must be symmetry in the molecule. different kinds of carbons and protons, I predicted that there must be symmetry in the molecule....
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