Practice Problems and Numerical Solutions

# Practice Problems and Numerical Solutions - 6 ° 1 − 2 °...

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Answers for Sample Second Midterm BEWARE: The following are just the numerical answers. Since the justiFcation is missing, they would not receive full credit on the real exam. 1: f xx =4+6 xy +2 y 4 , f xy =3 x 2 +8 xy 3 , f yy =12 x 2 y 2 ; saddle point. 2: ± 0 . 19. 3: ∂z ∂s =11 e 2 + 7 and ∂z ∂t =5 e 2 +1 4: f ( x, y, z )= ° 2 xyz 3 + z,x 2 z 3 , 3 x 2 yz 2 + x ² ;129 / 6; 50 x +8 y +37 z =148 .
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Unformatted text preview: 6: ° 1 − 2 ° 2 − y 2 y (6 + x + y 2 ) dx dy = 639 / 20 . 7. The region is given by 0 ≤ θ ≤ π/ 2 , 2 cos θ ≤ r ≤ 2. Then ° ° D y dA = ° π/ 2 ° 2 2 cos θ ( r sin θ ) rdrdθ = 8 3 ° π/ 2 sin θ (1 − cos 3 θ ) dθ = 2 ....
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## This note was uploaded on 09/07/2011 for the course MATH 39578 taught by Professor Penner during the Spring '09 term at USC.

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