Unformatted text preview: b = 4. By the division algorithm, a = 4 q + r for some r ∈ { , 1 , 2 , 3 } . If r = 0, then a = 4 q = 2(2 q ); so a is even (not odd). If r = 2, then a = 2(2 q + 2); so a is even (not odd). Therefore, a is of the form 4 k + 1 or 4 k + 3. (In fact, since r is unique, a has only one of these two forms). • 1.1 # 8 is similar to a problem that we solved in the lecture on 01/14/2011. • Appendix C # 2 was solved in class on 01/19/2011. • Appendix C # 12: The answer is false. 1...
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This note was uploaded on 09/08/2011 for the course MTH 310 taught by Professor R.bell during the Spring '10 term at Michigan State University.
 Spring '10
 R.Bell
 Algebra, Division

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