estatics2 - Motion of Charged Particle in an Electric Field...

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1 Electrostatics 2 otion of Charged Particle in Uniform Electric Field; Motion of Charged Particle in Uniform Electric Field; Electric Potential Energy & Electric Potential Motion of Charged Particle in an Electric Field if a particle of mass m and charge q is placed in an lectric field, it will feel a force = q and electric field, it will feel a force F E q E , and accelerate accordingly thus q E = m a , or a = q/m E if E is uniform (constant in magnitude and (g direction), then the particle’s acceleration is constant (kinematic equations apply !!) if q is + for the particle, then it accelerates in the direction of E if q is -, its acceleration is opposite to the direction of E Positive Particle Moving in Uniform Electric Field consider simple electric field that is uniform (constant in magnitude and direction) like that between two charged plates imagine a proton in that field It will be repulsed from one late attracted to other : so net plate, attracted to other : so net force directed towards the negative plate A positive charge q, mass m, is released from rest in a uniform electric field E directed along the x-axis as shown. Describe its motion using kinematic equations.
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2 Clicker: A positive point charge + Q is released from rest in an general electric field. At any later time, the velocity of the point charge 1. is in the direction of the electric field at the position f the point charge of the point charge 2. is directly opposite the direction of the electric field at the position of the point charge 3. is perpendicular to the direction of the electric field at the position of the 12345 0% 0% 0% 0% 0% 0 of 5 p point charge 4. is zero 5. not enough information given to decide 20 Applying the kinematic equations for constant acceleration in uniform E field for a charged projectile (neglecting gravity) with v o @ E Applying the kinematic equations for constant acceleration in uniform E field for a charged projectile (neglecting gravity) with v o @ E Example: An electron enters the region of a uniform electric field with v o = 3.00 x 10 6 m/s and E = 200 N/C. The horizontal length of the plates is L = 0.1 m. Find the acceleration of the electron, and the length of time the electron is in the field.
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3 Example: An electron enters the region of a uniform electric field with v o = 3.00 x 10 6 m/s and E = 200 N/C. The horizontal length of the plates is L = 0.1 m. Find the acceleration of the electron, and the length of time the electron is in the field. Gravitational Force near Earth’s surface F = m gg = - g j = - 9.8 m/s 2 j Recall: Gravitational Force & Potential Energy: special form (near Earth’s surface) g vector Gravitational potential energy near Earth’s surface U g = mgh r a mass m at a height h above Earth’ssurface for a mass m at a height h above Earth s surface Scalar Reference point is U o = 0 at h=0 Gravitational Force: general form (not near Earth’s surface) ˆ Fr GMm  Gravitational force for any distance r from centre of Earth 2 g r Gravitational Potential Energy: general form (not near Earth’s surface)
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estatics2 - Motion of Charged Particle in an Electric Field...

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