# Part4 - Chng 4 KHUECH AI CONG HNG I BO KHUECH AI CONG HNG N...

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24 Chöông 4 : KHUEÁCH ÑAÏI COÄNG HÖÔÛNG I) BOÄ KHUEÁCH ÑAÏI COÄNG HÖÔÛNG ÑÔN : Giaû thieát r bb’ = 0. R p = ω 0 LQ C (1); ω 0 = LC 1 (2) C = C’ + C b’e + C b’c1 (1 + g m . L C L C R R R R + ) (3) A im R = r i // R p // R b // r b’e (4); Q i = ω 0 RC (5) ω L ω 0 ω H ω A i = - + ω 0 0 1 i im jQ A (6); BW ' = RC 1 r b’e

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25 A im = -g m .R. L C C R R R + (7) BW = RC π 2 1 (8); GBW = L C C m im R R R C g BW A + = . 2 . (9) II) PHOÁI HÔÏP TRÔÛ KHAÙNG ÑEÅ TAÊNG ÑOÄ LÔÏI : ' b R = R b // r b’e (1) R = r i // R p // 2 ' a R b (2) ) . 1 ( ' ' ' L C L C m c b e b b R R R R g C C C + + + = (3); C = C’ + a 2 C ' b (5) Tyû soá bieán aùp : a = 1 2 1 1 ' < = n n V V e b (4)
26 Q i = ω 0 RC (6); ) ' ( ' 1 ' 1 ' 2 2 0 b C a C L C L + = = ω (7) A i = - + 0 0 1 i im jQ A (8);A im = -ag m .R. L C C R R R + (9’) (R C ~R L ) BW = f H – f L = RC π 2 1 (10); GBW = im A .BW (11) * Ví duï H 4-8 a = 2 1 1 ' n n V V e b = (1); 2 1 n n V V Lm = (2); 1 ' n n V V e b Lm = (3) a = 2 1 1 2 ' 1 1 ' . n

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Part4 - Chng 4 KHUECH AI CONG HNG I BO KHUECH AI CONG HNG N...

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