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# Prob6 - 7.17 C1 Gia thiet RA = RB R1 R2 V O/K va B ay la...

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133 Giaû thieát : R A = R B vaø Q C C R R 2 1 2 1 = = ñay laø OP-AMP khueách ñaïi khoâng ñaûo : 2 1 1 R R 1 k A B = + = + = (1) 7.17 V1 A B + V O/K Vo C1 R1 + - Vi R2 R R ) 1 s C R ( 2 V V ) 2 ( 1 s C R V 2 V 1 s C R 1 k V 2 2 o 1 2 2 1 1 2 2 O + = + = + = Toång doøng taïi nuùt 1: 0 s C 1 V V R V k V R V V 1 1 O 2 1 O 1 1 i = - + - + - (3) ) 4 ( 0 ) 1 s C R ( 2 s C V ) 1 s C R ( R 2 V ) 1 s C R ( R 2 V s C V R 2 V R V 2 2 1 1 2 2 2 O 2 2 1 O 1 O 2 o 1 i = + - + - + - + + Θ ) 5 ( 0 2 s C V R 2 s R R C C V R 2 V R 2 s C V R 2 V 2 s C R V s R C V R 2 R V V 1 O 1 2 2 1 2 1 O 2 O 1 2 O 1 O 2 2 o 1 1 O 2 1 o i = - - - - - - + + Θ ) 6 ( 0 s R R C C V Q V s C R V V s C R V s R C V Q V V 2 2 2 1 2 1 O O 2 1 O O 2 2 O 1 1 O o i = - - - - - + + Θ ) 7 ( 1 ] C R C R R C [ s s R R C C 2 V V A 2 1 2 2 1 1 2 2 1 2 1 i O v + + + + = =

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134 a_Tìm H oLp , o ω , Q khi C 1 = C 2 =C; R 1 = R 2 = R 3 = R 4 = R A oL = -> v + = v - =0 - > V 3 = 0 (1); Z i = barb4right i d = 0 ta coù : barb4right ) 8 ( R C Q 1 R C Q 1 QR R QC C 1 R R C C 1 2 2 2 O 2 2 2 2 2 2 2 1 2 2 1 2 1 2 O = ω = = = ω Töø (7) [ ] Q s C R C R R C s o ω = + + - 2 1 2 2 1 1 ) 9 ( 1 2 2 1 1 2 1 2 1 1 1 2 2 1 1 2 1 2 2 2 1 2 1 R C R C R C C R C R
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Prob6 - 7.17 C1 Gia thiet RA = RB R1 R2 V O/K va B ay la...

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