Homework 6v4

# Homework 6v4 - EE40 Summer 2011 Homework 6 Neel Shah Due...

This preview shows pages 1–2. Sign up to view the full content.

EE40 Summer 2011 Neel Shah Homework 6 Due 8/10/2011 Problem 0. iClicker Serial Number The friendly folks at iClicker decided to wipe out all class databases. Rather than trust them again with your iClicker information I’d prefer to take your serial numbers here. Please submit this information with your assignment. Problem 1. A Circuit Paradox Examine the schematic of a voltage source charging an initially uncharged capacitor. This should be an energy conserving circuit, since we have drawn no dissipative elements (i.e. resistors). The power supplied by the source is g G = ±² . Integrated over time, the energy supplied is ³ g G ´µ · = ± ³ ²´µ · = ¸± Where ¸ is the net charge the voltage source has delivered. The delivered charge now sits across the plates of the capacitor ¹ , and the stored energy in the capacitor is ³ g º ´µ = ³ ± ∙ ¹ ´± ´µ ´µ · = ¹ ³ ±´± · = 1 2 ¹± » · = 1 2 ¸± 50% of our energy has disappeared, which contradicts our expectation that the circuit conserve energy. What is the reason behind this paradox? (Hint: What about the schematic drawn differs from reality?)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 09/09/2011 for the course EECS 40 taught by Professor Chang-hasnain during the Summer '08 term at Berkeley.

### Page1 / 2

Homework 6v4 - EE40 Summer 2011 Homework 6 Neel Shah Due...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online