EE40 Lecture 04 - Mostly Thevenin

# EE40 Lecture 04 - Mostly Thevenin - EE40 Lecture 04 Thvenin...

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EE40 Lecture 04 Thévenin and Friends Neel Shah 6/27/2011

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Hi Sorry I’m late
Some things My office hours are in 212 Cory, MWF 10-11 HW1 is due at 5PM in the 240 Cory box Lab2 starts Tuesday, prelab is due at the beginning of your lab session on Tuesday Lab1 writeup is due in your lab session on Wednesday Get yer iClickers and get to participatin’

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Let’s play a game
iClicker test Do you have an iClicker? A: Yes B: yes D: None of the above This is what I see…

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Quick Review: Superposition Superposition is the process of adding contributions of each energy source Superposition is valid for any linear system F(ax+by) = aF(x) + bF(y); this is the same thing! Linearity means the I-V curve of all components (resistors etc) are flat Can find net branch current or net node voltage by examining the branch current or node voltage when only one source is active
Superposition Procedure : 1. Determine contribution due to one independent source • Set all other sources to 0: • Replace independent voltage source by short circuit • independent current source by open circuit 2. Repeat for each independent source 3. Sum individual contributions to obtain desired voltage or current

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Easy Example • Find V o 12 Ω 4 Ω 4 A 4 V + – + V o 12 Ω 4 Ω 4 V + – + V o Voltage Divider: -1V
Easy Example • Find V o 12 Ω 4 Ω 4 A 4 V + – + V o 12 Ω 4 Ω 4 A + V o Current Divider: -(3A*4Ω)=-12V

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Easy Example • Find V o 12 W 4 W 4 A 4 V + – + V o V 0 =-12V-1V=-13V Due to current source Due to voltage source
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EE40 Lecture 04 - Mostly Thevenin - EE40 Lecture 04 Thvenin...

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