111E3-S2010 - MA 11100 1) Exam 3A Spring 2010 Solve the...

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MA 11100 Exam 3A Spring 2010 1 1) Solve the inequality below. Write the solution using interval notation. 3( 4) 2 7 x x - + + - ( ) ( ( ) ( 7 2 17 2 17 2 7 2 17 2 , , , , , A B C D E -∞ - -∞ -∞ - 2) Solve 2 16 22 6 x - - = - Which statement describes the solution(s)? There is no solution. There are two solutions; one positive, the other zero. There is only one solution; it is positive. There are two positive solutions. There is only one solution; it is zero. A B C D E 3) Let 1 2 ( ) 4 f x x = - . Find all values for which ( ) 5 f x . 1 9 2 2 1 9 2 2 { | 2 18} { | } { | 1 9} { | 2 or 18} { | or } A x x B x x C x x D x x x E x x x - ≤ - - ≤ ≤ - ≤ -
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MA 11100 Exam 3A Spring 2010 2 4) Subtract: 2 2 ( 6 8 5) (7 5 8) m m m m - - + - - - 2 2 2 2 15 3 15 13 11 15 3 11 3 None of the above. A m m B m m C m m D m m E - - - - - + - - - - - - 5) Which of the following is(are) false ? ( ) ( ) 3
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This note was uploaded on 09/11/2011 for the course MATH 111 taught by Professor Staff during the Spring '09 term at Purdue University-West Lafayette.

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111E3-S2010 - MA 11100 1) Exam 3A Spring 2010 Solve the...

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