152E2-S2010

152E2-S2010 - MA 15200 1) Exam 2A A mechanic, Louis, needs...

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MA 15200 Exam 2A Spring 2010 1 1) A mechanic, Louis, needs 15 Liters of a solution that is 50% antifreeze. Unfortunately, there are only 30% antifreeze and 85% antifreeze solutions available. Louis believes he can use his algebra knowledge to determine how much of the 30% antifreeze and how much of the 85% antifreeze he needs to mix in order to get the desired strength of 50% antifreeze. If x represents the amount (in Liters) of 30% antifreeze, which equation could be used to solve for x ? 0.3 0.85(15 ) 15 0.3 0.85(15 ) 0.5 0.3 0.85 7.5 0.3 0.85(15 ) 7.5 0.3 0.85( 15) 7.5 A x x B x x C x x D x x E x x + - = + - = + = + - = + + = 2) Divide and write answer in standard ( ) a bi + form. 2 3 4 i i - + 8 6 7 7 6 8 25 25 8 6 25 25 8 6 25 25 8 6 7 7 A i B i C i D i i E i + - - - - - + - - 3) Solve. Write solution(s) in simplified form. 2 3 6 4 0 a a - - = 21 1 3 1 2 21 21 1 3 6 21 3 3 1 3 i i A a B a C a D a E a = ± = ± = ± ± = = ±
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MA 15200 Exam 2A Spring 2010 2 4) After completing the square, the equation
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This note was uploaded on 09/11/2011 for the course MATH 152 taught by Professor staff during the Fall '09 term at Purdue.

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152E2-S2010 - MA 15200 1) Exam 2A A mechanic, Louis, needs...

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