Chapter 2 CW - 2 b. =60, o=5 For 50 -2 For 70 2 For 80 4 c....

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Valerie Bodden K. 10-0014 Statistics May 24, 2010 Chapter 2 exercises, page 101. 151,152,157,158,161,162,173,175,179,180,189,191 151. Discuss conditions under which the median is preferred to the mean as a measure of central tendency. When extreme observations exist, they alter the mean making it less favorable to use. The median would be preferred in this situation. 152. Explain why we generally prefer the standard deviation to the range as a measure of variation. Because range is a measurement of the whole data, the distance, it includes everything without specifying the expected variations from the mean. 157. Consider the following three measurements: 50, 70, 80. Find the z-score for each measurement of they are from a population with a mean and standar deviation equal to: Z= x- µ o a. µ=60, o=10 for 50 -1 for 70 1 for 80
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Unformatted text preview: 2 b. =60, o=5 For 50 -2 For 70 2 For 80 4 c. =40, o=10 For 50 1 For 70 3 For 80 4 d. =40, o=100 For 50 .1 For 70 .3 For 80 .4 158. Refer to Exercise 2.157. For parts a-d determine whether the three measurements 50, 70, 80 are outliers. For a There is not outlier. For b 80 would be an outlier. For c Both 70 and 80 would be an outlier. For d There is not outlier. 161. For each of the data sets in parts a-c compute and x, s 2 , and s. If appropriate, specify the units in which your answers are expressed. a. 4, 6, 6, 5, 6, 7 Mean: 5.67 Varience: 4 - 5.67= -1.67, (squared)= -2.7889 6 - 5.67= 0.33, (squared)= 0.1089 5 - 5.67= -0.67(squared)= -0.4489 7 5.67= 1.33 (squared)= 1.7689 total sum: 34, total sum squared: 196 Std.Dev.: 0.67 162....
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Chapter 2 CW - 2 b. =60, o=5 For 50 -2 For 70 2 For 80 4 c....

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