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Unformatted text preview: positive abscissa, and 0 to 80 kPa on the positive ordinate. Hint: see my Mohr02 in “300 Solved Problems” notes; 2) Draw the first Mohr circle “i” on the gridruled background. Notice that since, and K o = 0.5, if the normal stress σ n = σ 1 = 65 kPa, then σ 3 = 32.5 kPa; 3) The failure point “ F ” shows the result of holding the same normal stress, but adding a shear stress of 41 kPa. Now, you can prove that the angle of internal friction φ = 32º. 4) Since the failure circle passes through “F”, find the center of that circle. See if you get a coordinate of 91 kPa, 0. Now find the maximum and minimum principal stresses for the failure circle (these should be 139 and 43 kPa respectively). Check your results with the figure shown on the next page. 5) Would an assumption that the failure plane is horizontal be a good one? Why?...
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 Summer '10
 STAFF
 Force, kPa, normal stress

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