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Unformatted text preview: Physics 6A Work and Energy examples Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB 1) A boy exerts a force of 11.0N at 29.0 degrees above the horizontal on a 6.40kg sled. Find the work done by the boy and the final speed of the sled after it moves 2.00m, assuming the sled starts with an initial speed of 0.500m/s and slides horizontally without friction. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB 1) A boy exerts a force of 11.0N at 29.0 degrees above the horizontal on a 6.40kg sled. Find the work done by the boy and the final speed of the sled after it moves 2.00m, assuming the sled starts with an initial speed of 0.500m/s and slides horizontally without friction. 29 F=11N Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB 1) A boy exerts a force of 11.0N at 29.0 degrees above the horizontal on a 6.40kg sled. Find the work done by the boy and the final speed of the sled after it moves 2.00m, assuming the sled starts with an initial speed of 0.500m/s and slides horizontally without friction. 29 F=11N Initially the sled is moving at 0.5 m/s, so its kinetic energy is: ( 29 ( 29 J 8 . 5 . kg 4 . 6 mv K 2 s m 2 1 2 2 1 = = = Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB 1) A boy exerts a force of 11.0N at 29.0 degrees above the horizontal on a 6.40kg sled. Find the work done by the boy and the final speed of the sled after it moves 2.00m, assuming the sled starts with an initial speed of 0.500m/s and slides horizontally without friction. 29 F=11N Initially the sled is moving at 0.5 m/s, so its kinetic energy is: ( 29 ( 29 J 8 . 5 . kg 4 . 6 mv K 2 s m 2 1 2 2 1 = = = Next we can find the work done by the boys pull, and add that to the kinetic energy. Remember work always equals the change in the kinetic energy. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB 1) A boy exerts a force of 11.0N at 29.0 degrees above the horizontal on a 6.40kg sled. Find the work done by the boy and the final speed of the sled after it moves 2.00m, assuming the sled starts with an initial speed of 0.500m/s and slides horizontally without friction. 29 F=11N The force is not aligned with the motion, so we need to use the xcomponent to get the work. ( 29 ( 29 ( 29 ( 29 J 24 . 19 m 2 29 cos N 11 W d cos F W = = = Initially the sled is moving at 0.5 m/s, so its kinetic energy is: ( 29 ( 29 J 8 . 5 . kg 4 . 6 mv K 2 s m 2 1 2 2 1 = = = Next we can find the work done by the boys pull, and add that to the kinetic energy. Remember work always equals the change in the kinetic energy. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB 1) A boy exerts a force of 11.0N at 29.0 degrees above the horizontal on a 6.40kg sled. Find the work done by the boy and the final speed of the sled after it moves 2.00m, assuming the sled starts with an initial speed of 0.500m/s and slides horizontally without friction. 0....
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 Spring '07
 STANEK
 Energy, Force, Work

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