6A_Lecture_6

6A_Lecture_6 - Lecture 6 NMR Spectroscopy Experiment 6 For...

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Unformatted text preview: Lecture 6 NMR Spectroscopy Experiment 6 For 1 H NMR, choose solvent with no protons ◦ CDCl 3 , D 2 O (solvent must dissolve sample) Add a reference sample (TMS…CDCl 3 ok) 4-20 mg of sample in ~0.5 mL of solvent Shim the NMR (mag field same throughout) ◦ Spinning of the tube ensures homogeneity Integration ◦ Intensity of peak (area underneath signal) proportional to number of protons Splitting (signal to signal interaction) ◦ Use the N+1 rule N = number of hydrogens on the adjacent carbon..not other atoms! If N = 1…then according to the rule the splitting pattern equals 2, or a doublet If N = 2…then the splitting is 3, or a triplet Splitting Patterns and Coupling ◦ N+1 rule gives splitting Splitting intensity governed by Pascal's Triangle So what does NMR tell us?? ◦ Number of protons on the molecule ◦ What kind of atoms the protons are attached to ◦ The number of adjacent protons This is an extremely powerful tool!!!...
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This note was uploaded on 09/09/2011 for the course CHEM 6a taught by Professor Pettus during the Spring '07 term at UCSB.

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6A_Lecture_6 - Lecture 6 NMR Spectroscopy Experiment 6 For...

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