6A_Lecture_7

6A_Lecture_7 - Lecture 7 13 C NMR Mass Spectrometry...

Info iconThis preview shows pages 1–19. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Lecture 7 13 C NMR Mass Spectrometry Experiment 8: Combined Spectroscopy Abundance in nature is only 1.1% Need more sensitive instrumentation to detect Splitting patterns and integration not reliable Likelihood of having an adjacent 13C nuclei is low Coupling and splitting have been removed from 13C NMR 13C signal = 20 times the 1H equivalent 4 signals 5 signals 5 signals 5 signals Not a form of spectroscopy because light is not absorbed Involves removing an electron through electron impact (EI MS) Since there are different isotopes of atoms, they show up too. Abundance of 1 H is about 99.9% and 2 H is about 0.1% 13 C ~ 1.0% and 12 C ~99.0% Because of isotopes, we have a new term: Exact Mass The mass of the compound considering the highest isotope of each atom. Other smaller peaks in proximity represent isotopic differences in mass Mass Spectra and the Molecular Ion It would be difficult to differentiate between these two compounds using IR or NMR Using MS, each compound will have a different exact mass and different isotope pattern. Bromine: 79 Br : 81 Br 1:1 ratio Chlorine: 35 Cl : 37 Cl 3:1 ratio Particularly useful for detecting Bromine Same for chlorine Rule of Thirteen-...
View Full Document

Page1 / 43

6A_Lecture_7 - Lecture 7 13 C NMR Mass Spectrometry...

This preview shows document pages 1 - 19. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online