Quiz Week 02

Quiz Week 02 - Foundations- Week 2 Formative Quiz for PS2s...

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Foundations- Week 2 Formative Quiz for PS2s Total score: 10 out of 20, 50% Question 1 of 20 1. The CFTR gene product is a chloride channel expressed in lung and intestinal epithelial cells, as well as certain other cell types. One deletion mutant of the CFTR gene lacks almost all of the first intron of the gene but contains all 24 exons. The CFTR protein expressed from this mutant gene in lung and intestinal epithelial cells has the normal amino acid sequence. Microarrays indicate that the mutant CFTR gene is expressed at normal levels in lung cells, but that gene expression of the mutant CFTR gene in intestinal cells is reduced 60%. Which of the following is the most likely role of the deleted intron 1 sequences in the normal CFTR gene? A. Bind transcriptional activators active in intestinal cells but not active in lung cells. B. Bind transcriptional repressors active in intestinal cells but not active in lung cells. C. Bind translational initiation factors that are expressed in intestinal cells, but not in lung cells D. Bind translational inhibitors that are expressed in intestinal cells, but not in lung cells. E. Targeted by DNA methylases that methylate the CFTR gene in intestinal cells, but not lung cells. 1 out of 1 The correct answer is: A. Bind transcriptional activators active in intestinal cells but not active in lung cells. Question 2 of 20 2. Estrogen-activated estrogen receptors act as sequence-specific transcription factors to stimulate transcription of genes containing estrogen receptor binding sequences within their enhancers. Transcription of several genes in uterine cells increases in response to estrogen. What effect does estrogen stimulation have on the level of condensation of the chromatin of these genes? A. Modifies "beads-on-a-string" chromatin into 30 nm fiber chromatin. B. Modifies 30 nm fiber chromatin into chromosome loops.
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C. Modifies mitotically-condensed chromatin into chromosome loops. D. Decondenses nucleosome packing on "beads-on-a-string" chromatin. 1 out of 1 The correct answer is: D. Decondenses nucleosome packing on “beads-on-a-string” chromatin. Question 3 of 20 3. A single base pair substitution (TA to GC) in a human hemoglobin gene increased the level of hemoglobin activity (measured through O 2 binding) in developing red blood cells about three- fold. Microarray analysis indicated about a three-fold increase in expression of mRNA from the mutant hemoglobin gene, without significant changes in the expression of other genes. What mutation would best account for this combination of findings? A. A frameshift mutation within an exon of the hemoglobin gene. B. A silencer mutation that inactivates a sequence-specific repressor binding site. C. An enhancer mutation that inactivates a sequence-specific activator binding site.
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This note was uploaded on 09/14/2011 for the course PHARM HB taught by Professor Staff during the Spring '11 term at UCSD.

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Quiz Week 02 - Foundations- Week 2 Formative Quiz for PS2s...

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