159E1-S2011

# 159E1-S2011 - MA 15900 1 Find all the solutions of the...

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MA 15900 EXAM 1 SPRING 2011 1 1. Find all the solutions of the equation. x 4 = 16 1) x = 2 2) x = ± 2 3) x = 4 4) x = ± 4 5) x = 2 i 6) x = ± 2 i 7) x = 2,2 i 8) x = ± 2, ± 2 i 9) None of the above 2. Simplify the expression. 12 x 2 y 7 z 5 3 6 x 4 yz 5 3 1) 2 x 2 y 2 z 8 x 2 yz 3 2) 6 x 3 y 4 z 5 3 3) 2 x 2 y 2 z 3 y 2 z 3 4) 6 x 4 y 3 z 12 yz 3 5) x 2 y 2 z 3 18 y 2 z 3 6) 3 x 4 y 3 z 12 yz 3 7) x 2 y 2 z 8 18 x 2 yz 3 8) 3 x 3 y 4 z 5 3 9) None of the above 3. Factor the polynomial completely. 75 x 4 48 y 2 1) (15 x 2 + 12 y )(5 x 2 + 4 y ) 2) x 2 12 y )(5 x 2 4 y ) 3) 3(25 x 2 + 16 y )( x 2 y ) 4) 3(25 x 2 16 y )( x 2 + y ) 5) 3(5 x 2 4 y ) 2 6) 3(5 x 2 + 4 y ) 2 7) 3(5 x 2 2 y )(5 x 2 + 8 y ) 8) 3(5 x 2 4 y )(5 x 2 + 4 y ) 9) None of the above

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MA 15900 EXAM 1 SPRING 2011 2 4. Solve the equation. 1 x + 2 + 5 x 2 = 4 x 7 x 2 4 1) x = 1 2 2) x = 1 2 3) x = 15 4) x = 15 5) x = 15 2 6) x = 15 2 7) x = 7 2 8) x = 7 2 9) x = 13 4 5. Simplify the expression. 10 + 3 r r 2 r 4 + 8 r 1) 7 r 2 + 4 2) 7 r 2 + 4 3) (5 + r )(2 r ) r ( r 3 + 8) 4) (5 + r )(2 r ) r ( r 3 + 8) 5) r 5 r ( r 2 2 r + 4) 6) r 5 r ( r 2 2 r + 4) 7) 2( r + 5) ( r + 2)( r 2 2 r + 4) 8) 2( r + ( r + 2)( r 2 2 r + 4) 9) None of the above
MA 15900 EXAM 1 SPRING 2011 3 6. Express as a polynomial. (2 x 3 y ) 3 1) 8 x 3 12 x 2 y 18 xy 2 27 y 3 2) 8 x 3 12 x 2 y + 18 xy 2 27 y 3 3) 8 x 3 27 y 3 4) 4 x 2 12 xy + 9 y 2 5) 6 x 9 y 6) 8 x 3 24 x 2 y + 36 xy 2 27 y 3 7) 8 x 3 36 x 2 y + 54 xy 2 27 y 3 8) 8 x 3 18 x 2 y + 27 xy 2 27 y 3 9) None of the above 7. Solve the equation.

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159E1-S2011 - MA 15900 1 Find all the solutions of the...

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