159E3-S2010 - MA 15900 1 Solve the equation 2x 3 4 x 2 11x 7 = 2x EXAM 3 3 SPRING 2010 2 x 2 4 1 x = 3 5 4 3 2 x = 1 5 2 4 3 x = 2 1 5 2 4 x = 1 3

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MA 15900 EXAM 3 SPRING 2010 1 1. Solve the equation. 2 x 3 + 4 x 2 11 x + 7 = 2 x 3 2 x 2 + 4 1) x = 3 4 , 5 3 2) x = 1 2 , 5 4 3) x = 2 5 , 1 2 4) x = 1 3 , 3 2 5) x = 1 3 , 3 2 6) x = 2 5 , 1 2 7) x = 1 2 , 5 4 8) x = 3 4 , 5 3 9) No solution exists 2. A block of steel on a level, frozen pond, is given an initial speed V . Even though the block of steel is sliding on smooth ice, there will be a small friction force that will slow the block of steel until it comes to a stop. Assume that the distance, d , the block travels is directly proportional to the square of V . When V = 4 feet per second, d = 32 feet. Find the distance the block travels if the initial speed is 10 feet per second. 1) 16 10 feet 2) 80 feet 3) 100 feet 4) 112 feet 5) 132 feet 6) 200 feet 7) 400 feet 8) 432 feet 9) None of the above 3. How much money, invested at an interest rate of 8% per year compounded continuously, will amount to $65,000 in 17 years? Round your answer to the nearest cent. 1) $16,666.67 2) $16,682.95 3) $16,758.42 4) $17,567.48 5) $47,794.12 6) $88,400.00 7) $240,501.17 8) $252,112.14 9) $253,252.56
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MA 15900 EXAM 3 SPRING 2010 2 4. Which of the following is equivalent to 1 + tan θ sec ? 1) cos 2) sec 3) 1 + sin 4) cos + sin 5) 1 + 1 sin 6) 1 cos + 1 sin 7) cos + cos 2 sin 8) sin + sin 2 cos 9) cos + sin cos 2 5. Find an equation of a rational function, f , that satisfies the given conditions. Vertical asymptotes: x = 2 , x = 3 and x = 5 Horizontal asymptote: y = 0 x -intercept when: x = 1 f (0) = 4 5 1) f ( x ) = 24( x 1) ( x 2)( x + 3)( x + 5) 2) f ( x ) = ( x + ( x + 2)( x x 5) 3) f ( x ) = 2( x + 2)( x x 5) 75( x + 4) f ( x ) = ( x + 2)( x x
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This note was uploaded on 09/14/2011 for the course MATH 159 taught by Professor Staff during the Spring '09 term at Purdue University-West Lafayette.

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159E3-S2010 - MA 15900 1 Solve the equation 2x 3 4 x 2 11x 7 = 2x EXAM 3 3 SPRING 2010 2 x 2 4 1 x = 3 5 4 3 2 x = 1 5 2 4 3 x = 2 1 5 2 4 x = 1 3

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