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HW04-solutions - nunez(djn358 HW04 Radin(54915 This...

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nunez (djn358) – HW04 – Radin – (54915) 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 oF 4) 10.0 points A Calculus student begins walking in a straight line From the RLM building towards the PCL Library. AFter t minutes his velocity v = v ( t ) is given (in multiples oF 10 yards per minute) by the Function whose graph is 2 4 6 8 10 2 2 4 6 2 t v How Far is the student From the RLM build- ing at time t = 4? 1. dist = 90 yards correct 2. dist = 100 yards 3. dist = 110 yards 4. dist = 80 yards 5. dist = 130 yards Explanation: The student is walking towards the PCL Library whenever v ( t ) > 0 and towards RLM whenever v ( t ) < 0. The distance he has walked is given by 10 times the area between the graph oF v and the t axis since 1 unit is equivalent to 10 yards. Now at t = 4 this area is 9 units, so the student has walked a distance oF 90 yards. 002 (part 2 oF 4) 10.0 points How Far is the student From the RLM build- ing at time t = 7? 1. dist = 200 yards correct 2. dist = 190 yards 3. dist = 210 yards 4. dist = 240 yards 5. dist = 220 yards Explanation: The distance the student has walked is given by the area between the graph oF v and the t axis. Now at t = 7 this area is 20 units, so the student has walked a distance oF 200 yards. 003 (part 3 oF 4) 10.0 points What is the total distance walked by the student From time t = 0 to t = 10? 1. dist = 245 yards correct 2. dist = 225 yards 3. dist = 255 yards 4. dist = 275 yards 5. dist = 235 yards Explanation: The distance the student has walked is given by the area between the graph oF v and the t axis. Now at t = 10 this area is 24 . 5 units (area is always positive remember), so the student has walked a distance oF 245 yards. 004 (part 4 oF 4) 10.0 points How Far is the student From the RLM build- ing when he turns back? 1. dist = 265 yards 2. dist = 215 yards
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nunez (djn358) – HW04 – Radin – (54915) 2 3. dist = 195 yards 4. dist = 245 yards 5. dist = 225 yards correct Explanation: The student will turn back when his veloc- ity changes from postive to negative, i.e. , at t = 8. At this time he is 225 yards from the RLM building. keywords: distance, time, graph, velocity, area 005 10.0 points Determine the indeFnite integral I = i 2 6 x x dx . 1. I = 4 x 1 / 2 + 4 x 3 / 2 + C 2. I = 4 x 1 / 2 4 x 3 / 2 + C correct 3. I = 2 x 1 / 2 + 2 x 3 / 2 + C 4. I = 2 x 1 / 2 + 4 x 3 / 2 + C 5. I = 2 x 1 / 2 4 x 3 / 2 + C 6. I = 4 x 1 / 2 2 x 3 / 2 + C Explanation: After division we see that 2 6 x x = 2 x 6 x = 2 x 1 / 2 6 x 1 / 2 .
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HW04-solutions - nunez(djn358 HW04 Radin(54915 This...

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