{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Topic+18_CE+480+Traffic+Flow

Topic+18_CE+480+Traffic+Flow - CE 480 Transportation CE 480...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: CE 480 Transportation CE 480 Transportation Engineering Traffic Flow Fundamentals Fundamentals Fundamentals Primary Elements of Traffic Streams – Flow – Density Gap/headway – Speed Used in planning, designing and evaluating traffic engineering measures on a highway system Applications Applications Traffic flow theory is used for: – Design of left turn storage lengths in left turn lanes – Average delay at intersections, freeway ramp merging areas – Simulation Mathematical algorithms used to study complex interrelationships of a traffic stream – Estimate impacts of: Travel time and delay Air pollution Fuel consumption Traffic Flow (Q) Traffic Flow (Q) Flow (Q): hourly rate at which vehicles pass a point on a street/highway Q = n × 3600/T where: Q = hourly flow in vehicles per hour (vph) n = number of vehicles passing a point on the roadway in ‘T’ seconds Density (K) Density (K) Also referred to as concentration Number of vehicles traveling over a unit length of highway in an instant in time Unit length is usually 1 mile ∴ Unit of density is typically vehicles per mile (vpm) Speed (V) Speed (V) Distance traveled by a vehicle during a unit of time Expressed in mph or ft/sec Two types of speed – Time mean speed (Vt) – Space mean speed (Vs) SMS is always used in traffic flow theory applications SMS weights slower moving vehicles more heavily – Based on the amount of time they occupy the highway TMS is always greater than SMS Time Mean Speed (TMS) Time Mean Speed (TMS) Vt Average speed of all vehicles passing a point on a highway over a specified time period (point measure) Σ (d/ti) = i TMS = Σ (vi) i n Where, n TMS in ft/sec or miles/hr d = distance traveled (ft or mile) ti = travel time of ith vehicle (sec or hour) n = number of travel times observed Vi = speed of ith vehicle (fps or mph) Space Mean Speed (SMS) Space Mean Speed (SMS) Vs Average speed of all vehicles occupying a given section of highway over some specified time period­ describes a length d n of a highway Σ (ti)/n Σ (1/vi) SMS = where, SMS in ft/sec or miles/hr d = distance traveled (ft or mile) ti = travel time of ith vehicle (sec or hour) Time Headway (h) Time Headway (h) Difference between the time the front of a vehicle arrives at a point on the highway and the time the front of the next vehicle arrives at that same point Usually expressed in seconds Relationship between headway and flow h = 1/Q = 3600/Q 1 2 Time headway in seconds Space Headway (s) Space Headway (s) Distance between the front of a vehicle and the front of a following vehicle Usually expressed in feet Relationship with density (K) 1 2 s = 1 mile/K = 5280/K Space headway in feet Time and Space Headway Time and Space Headway 2 Gap 1 Space headway (spacing) in feet Time headway in seconds Fundamental Equation of a Vehicular Traffic Stream Q­K­V Relationship Q­K­V Relationship Flow (veh/hr) = Density (veh/mile) x Speed (miles/hr) Q = K x V Where, Q= Flow K= Density V= Speed (also denoted by ‘u’ or ‘s’) Traffic Stream Model SPEED­DENSITY Speed (mph) Behavior non­linear Vf Vf = free flow speed Kj = jam density Kj Density (veh/mile) Traffic Stream Model FLOW­DENSITY Flow (veh/h) dq/dk=0 @ max flow Qm Qm = maximum flow Km = optimum density 0 Km Kj Density (veh/mile) Basic Traffic Stream Models SPEED­FLOW Speed (km/h) Vf Qm = maximum flow Vm = optimum speed Vm 0 Qm Flow (veh/h) Q­K­V Curves Q­K­V Curves Flow (veh/hr) qmax Speed (miles/hr) Speed (miles/hr) Density (veh/mile) Density (veh/mile) Flow (veh/hr) Y = mX + b Slope of V­K line is (Vf/Kj) Vf V1 Vm V2 I Area under the speed­ density curve is flow Optimum Flow II Kj Qmax Q1 = Q1 Flow Speed Q­K­V Relationship Q­K­V Relationship K1 Km Density K2 Qmax is considered to be the ‘capacity’ of a roadway K1V1 K2V2 Typical ranges of jam density are: 180 vpmpl < Kj < 225 vpmpl (vpmpl) = veh per mile per lane Free Flow Speed Free Flow Speed Varies based on: – Type of facility – Time of day Some constrictions include: – Presence of police officers, speed capabilities of vehicle, friction, road curvature, etc. – Avg. free flow speeds on highway ≈ 75 to 80 MPH – On residential streets free flow speed ≈ 35 MPH Constrictions may include more curves, presence of children, etc. Greenshield’s Model Greenshield’s Model Macroscopic approach Linear relationship between speed and density Vs = Vf – (Vf/Kj)K Derived formulas: Km = Kj/2 Vm = Vf/2 Qmax = KjVf/4 Where: Vs = Space mean speed, also referred to as V Vf = free flow speed Kj = jam density Km = density at which max flow occurs Qmax = maximum flow Example 1: Greenshield’s Example 1: Greenshield’s Model Given: Find: – – – Qm Vm Kj V = 54.5 – 0.24 K – havg at Qmax – savg at Qmax – space gap at Qmax At Q = 2,500 VPH, what are the values for K and V? Example 2: Greenshield’s Example 2: Greenshield’s Model Given: V and K are linearly related – V1 = 45 MPH, K1 = 60 VPM – V2 = 30 MPH, K2 = 105 VPM Compute: – – – – – K and V at Q = 1500 VPH Vf Qmax V1 havg at Qmax savg at Qmax V2 K at V = 65 mph Speed Y = mx + b (60,45) (105, 30) K1 K2 Kj Greenburg’s Model Greenburg’s Model Basic equation V = Vm ln(Kj/K) Example 3: Greenburg’s Example 3: Greenburg’s Model Given: V = 17.2 ln(228/K) Compute: Qm, Km, Vm and Kj Since Q = KV, Q = K[17.2 ln (228/K)] = 17.2[K ln(228/K)] dQ/dK = 17.2[K(­1/K) + (ln 228 – lnK)] dQ/dK = 0 ⇒Km 17.2 [­1 + (ln 228 – ln Km)] = 0 [­1 + (ln 228 – ln Km)] = 0 Ln Km =ln 228 – 1 = ln 228 – ln e Ln Km = ln (228/e) ∴ K = (228/e) = 84 VPM Proof of Greenburg’s Model Example 3: Greenburg’s Model Compute Vm at K = Km, V = Vm by definition ∴ Vm = 17.2 ln (228/Km) = 17.2 ln [228/(228/e)] = 17.2 ln e V = 17.2 MPH m OR Vm = 17.2 ln (228/84) = 17.2 MPH Example 3: Greenburg’s Model Compute Qmax Qmax = VmKm = 17.2 MPH x 84 VPM = 1,445 VPH Compute Kj At Kj, V = 0 V = 17.2 ln (228/Kj) = 0 ln (228/Kj) = 0 e0 = 228/Kj = 1 K = 228 j ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern