EE331HW1solutions - EE-331 Devices and Circuits 1 Prof. R....

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(b) n iSi 300 K ( ) 6.725 10 9 × cm 3 = n iGe 300 K ( ) 2.267 10 13 × cm 3 = (c) n iSi 500 K ( ) 8.363 10 13 × cm 3 = n iGe 500 K ( ) 8.036 10 15 × cm 3 = Problem 3: Problem 2.10 of Jaeger and Blalock. E 2500 volt cm 1 := µ n 700 cm 2 volt 1 sec 1 := µ p 250 cm 2 volt 1 sec 1 := n1 0 17 cm 3 := p1 0 3 cm 3 := v n µ n E := v n 1.75 10 6 × cm sec 1 = v p µ p E := v p 6.25 10 5 × cm sec 1 = J n q n v n := J n 2.803 10 4 × amp cm 2 = J p qp v p := J p 1.001 10 10 × amp cm 2 = EE-331 Devices and Circuits 1 Prof. R. B. Darling Homework # 1 Solutions First, define some useful units and constants: µ m1 0 6 m := eV 1.602 10 19 joule := k B 8.62 10 5 eV K 1 := q 1.602 10 19 coul := Problem 1: Problem 2.3 of Jaeger and Blalock. Note the corrected value of J max from the text. J max 10 mA ⋅µ m 2 := A 5.0 µ m 1.0 m := A51 0 8 × cm 2 = I max J max A := I max 50 mA = Problem 2: Problem 2.6(a,b,c) of Jaeger and Blalock.
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EE331HW1solutions - EE-331 Devices and Circuits 1 Prof. R....

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