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EnderecamentoIPSemClasse_CIDR_2011

# EnderecamentoIPSemClasse_CIDR_2011 - Figure 5.1...

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TCP/IP Protocol Suite 1 Figure 5.1 Variable-length blocks

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TCP/IP Protocol Suite 3 Table 5.1 Table 5.1 Prefix lengths Prefix lengths

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TCP/IP Protocol Suite 4 What is the first address in the block if one of the addresses is 167.199.170.82/27 ? Example 4 Address in binary: 10100111 11000111 10101010 01010010 Keep the left 27 bits: 10100111 11000111 10101010 010 00000 Result in CIDR notation: 167.199.170.64/27 Solution The prefix length is 27, which means that we must keep the first 27 bits as is and change the remaining bits (5) to 0s. The following shows the process:
5 What is the first address in the block if one of the addresses is 140.120.84.24/20 ? Example 5 See Next Slide Solution Figure 5.3 shows the solution. The first, second, and fourth bytes are easy; for the third byte we keep the bits corresponding to the number of 1s in that group. The first address is

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EnderecamentoIPSemClasse_CIDR_2011 - Figure 5.1...

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