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Lecture+11

# Lecture+11 - 440:221 Intro to Engineering Mechanics Statics...

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440:221 Intro to Engineering Mechanics: Statics Instructor: Alberto Cuitino TA: Pam Carabetta and Jingru Zhang Lecture 11 Fall 2009 1 Based on Textbook Material: Engineering Mechanics Statics, 12 th Edition, R.C. Hibbeler, Pearson 2010.

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440:221 Lectures opics to be covered Topics to be covered • What is the difference between a distributed and a concentrated load? • Can a distributed load be simplified as a concentrated load? When? • How do we find equivalent concentrated load? • Where is the application point? • How do we find it? School of Engineering, Fall 2009 2

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440:221 Lectures reliminary Questions (reading quiz) 1. The resultant force (F R ) due to Distributed load curve y Preliminary Questions (reading quiz) a distributed load is equivalent to the _____ under e distributed loading curve, w the distributed loading curve, w = w(x). A) Centroid B) Arc length x F R C) Area D) Volume C) Area 2. The line of action of the distributed load’s equivalent force passes through the ______ of the distributed load. School of Engineering, Fall 2009 A) Centroid B) Mid-point C) Left edge D) Right edge A) Centroid
440:221 Lectures pplications Applications … There is a bundle (called a bunk) of 2” x 4” boards stored on a storage o analyze the load’s effect on the steel beams it is often rack. This lumber places a distributed load (due to the weight of the wood) on the beams holding the bunk. School of Engineering, Fall 2009 To analyze the load s effect on the steel beams, it is often helpful to reduce this distributed load to a single force. How would you do this?

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440:221 Lectures pplications Applications … The uniform wind pressure is acting on a iangular sign (shown in triangular sign (shown in light brown). To be able to design the joint
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Lecture+11 - 440:221 Intro to Engineering Mechanics Statics...

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