Assignment 3 sol

Assignment 3 sol - 48 57 65 71 77 2.5 13 28 40 51 58 68 72...

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Q1. Solution a) Assume particles A and B with same densities: For laminar flow, Ratio of settling velocities = Vt a / Vt b = (0.4) 2 / (0.9) 2 = 0.198 For turbulent flow, Ratio of settling velocities = Vt a / Vt b = (0.4) 0.5 / (0.9) 0.5 = 0.667 Q2. Solution Since X r = V t / V c = V ta / V tb => For laminar flow, the removal efficiency of particle A = 19.8% => For turbulent flow, the removal efficiency of particle B = 66.7%
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Q3. Solution % removal at each depth and time, X ij = (1-C ij /C o ) *100 Depth (m) Time (min) 0 40 80 120 160 200 240 280 .5 0 55 71 85 87 92 95 96 1 0 46 55 66 74 80 86 89 1.5 0 23 42 56 65 72 78 82 2 0 18 32
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Unformatted text preview: 48 57 65 71 77 2.5 13 28 40 51 58 68 72 3 12 25 35 44 52 61 68 3.5 10 20 30 40 49 56 63 Flow Rate = 11.2 m 3 /day = 7.78 m 3 /min HRT = 1400 m 3 / 7.78 m 3 /min Then, we draw an iso-concentration curve similar to your notes. (Please refer to notes) Refer to the figure, ∆ r Z ∆ r*z 0.06 3.3 .198 0.1 2.45 .245 0.1 1.7 .17 0.1 1.05 .105 0.1 .625 0.0625 0.1 .175 0.0175 Total = 0.798 Hence, the removal efficiency = 0.44 + (0.798/3.5) = 0.668 = 66.8%...
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Assignment 3 sol - 48 57 65 71 77 2.5 13 28 40 51 58 68 72...

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