HW08_Solutions - triesault(njt298 H08 VSEPR and VB...

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triesault (njt298) – H08: VSEPR and VB – McCord – (53740) 1 This print-out should have 24 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points Consider a 3-atom molecule A B A For which B has a total oF only Four valence elec- trons – enough to make two bonds. Predict the A-B-A bond angle. 1. 60 2. 180 correct 3. 109.5 4. 120 5. 90 Explanation: 002 10.0 points What is the shape oF COCl 2 ? 1. trigonal planar correct 2. T-shaped 3. tetrahedral 4. seesaw 5. trigonal pyramidal Explanation: There are three regions oF electron density (with no lone pairs) around the central atom: C Cl b Cl O b b 003 10.0 points Which oF the Following has bond angles slightly LESS than 120 ? 1. SO 3 2. 2 3. O 3 correct 4. NO 3 5. I 3 Explanation: While SO 3 and O 3 have three regions oF electron density around the central atom, only O 3 has a lone pair in one oF these regions. The lone pair repels the other bonds more, which makes their angle slightly less than 120 . 004 (part 1 oF 2) 10.0 points Draw the Lewis structure For NO 2 . How many single bonds, double bonds, triple bonds, and unshared pairs oF electrons are on the central atom, in that order? 1. 0; 1; 1; 0 2. 4; 0; 0; 0 3. 3; 0; 0; 1 4. 0; 2; 0; 0 5. None oF these 6. 2; 0; 0; 2 7. 1; 1; 0; 1 correct 8. 0; 0; 1; 1 9. 1; 0; 1; 0 10. 2; 1; 0; 0 Explanation: N has 5 valence electrons and O has 6 va- lence electron. The total number oF valence electrons in the ion (plus one to account For the ion’s negative charge) is
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triesault (njt298) – H08: VSEPR and VB – McCord – (53740) 2 5 + (2 × 6) + 1 = 18 The Lewis structure for NO 2 can be found by connecting the oxygen atoms to nitrogen and placing eight electrons around each atom: b O b b b N b b O B and the central atom has one single bond, one double bond, and one unshared pair of electrons. 005 (part 2 of 2) 10.0 points Determine the molecular geometry of the ion NO 2 . 1. linear 2. None of these 3. bent or angular correct 4. trigonal-planar 5. octahedral 6. trigonal-bipyramidal 7. trigonal-pyramidal 8. tetrahedral Explanation: The central atom N has 2 bonding regions and 1 lone pair of electrons. The three areas of high electron density make the electronic geometry trigonal planar and the molecular geometry bent or angular: N O O 006 10.0 points
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HW08_Solutions - triesault(njt298 H08 VSEPR and VB...

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