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Unformatted text preview: CSE 110 – Midterm Exam 1 – Form B Fall 2010 ANSWER KEY NAME (please print legibly): Your University ID Number: NO BS bonus: If you do not know the answer to a problem and leave it blank you will receive 1 point for each part (e.g., a,b,c, etc.) that you leave blank. If you write anything in the space and it is wrong, you will receive a 0. You will not lose any points for small coding details or occasional misspellings. QUESTION VALUE SCORE 1 6 2 6 3 14 4 6 5 12 6 6 7 6 8 6 9 6 10 6 11 8 12 6 13 6 14 6 15 10 TOTAL 110 1 1. (6 points) What output is produced by the following code fragment? NOTE: indentation may be misleading! int limit = 100; int num1 = 20; int num2 = 20; if (limit <= limit) { if (num1 == num2) System.out.print("lemon "); System.out.print("lime "); } System.out.println("grape"); (a) lemon lime grape (b) grape (c) lime grape (d) lemon lime ANSWER: A 2. (6 points) The hexadecimal value 92 represents a two’s complement binary value. Translate this value into base 10. You must show your work in order to receive any credit for this problem. 92 = 1001 0010 = 10010010 = 128 + 16 + 2 = 110 (Assign 3 points if the student translates the value as unsigned binary instead, getting 146 or 146 as an answer) 2 3. (14 points) Translate 100.5 into 32bit floating point representation and convert the result into hexadec imal notation. Remember that 32bit representation has 1 sign bit, an 8bit exponent (with a bias of 127), and a 23bit mantissa field. You must show your work in order to receive partial (or any) credit....
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 Spring '08
 SHAUNAKPAWAGI
 Computer Science, Binary numeral system, Decimal, mantissa

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