2_Cal_Solution of Calculus_6e

2_Cal_Solution of Calculus_6e - a − 1) = 0; 2 a + 1 = 0...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
1 2 a 1 =5; 1=5 · (2 a 1); 1=10 a 5; 10 a =6; a = 3 5 . C01S01.007: If g ( x )= x 2 + 16 and g ( a ) = 5, then: p a 2 +16=5; a 2 + 16 = 25; a 2 =9; a =3or a = 3 . C01S01.008: If g ( x )= x 3 3 and g ( a ) = 5, then a 3 3=5,so a 3 = 8. Hence a =2. C01S01.009: If g ( x )= 3 x +25=( x + 25) 1 / 3 and g ( a ) = 5, then ( a + 25) 1 / 3 =5; a +25=5 3 = 125; a = 100 . C01S01.010: If g ( x )=2 x 2 x + 4 and g ( a ) = 5, then: 2 a 2 a +4=5; 2 a 2 a 1=0; (2 a + 1)(
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: a − 1) = 0; 2 a + 1 = 0 or a − 1 = 0; a = − 1 2 or a = 1 . C01S01.011: If f ( x ) = 3 x − 2, then f ( a + h ) − f ( a ) = [3( a + h ) − 2] − [3 a − 2] = 3 a + 3 h − 2 − 3 a + 2 = 3 h. C01S01.012: If f ( x ) = 1 − 2 x , then 2...
View Full Document

This note was uploaded on 09/14/2011 for the course MATH 101 taught by Professor Cheng during the Spring '11 term at Ecole Hôtelière de Lausanne.

Ask a homework question - tutors are online