12_Cal_Solution of Calculus_6e

12_Cal_Solution of Calculus_6e - Section 1.2 C01S02.001:...

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Section 1.2 C01S02.001: The slope of L is m =(3 0) / (2 0) = 3 2 ,so L has equation y 0= 3 2 ( x 0); that is, 2 y =3 x. C01S02.002: Because L is vertical and (7 , 0) lies on L , every point on L has Cartesian coordinates (7 ,y ) for some number y (and every such point lies on L ). Hence an equation of L is x =7. C01S02.003: Because L is horizontal, it has slope zero. Hence an equation of L is y ( 5) = 0 · ( x 3); that is, y = 5 . C01S02.004: Because (2 , 0) and (0 , 3) lie on L , it has slope (0 + 3) / (2 0) = 3 2 . Hence an equation of L is y 0= 3 2 ( x 2); that is, y = 3 2 x 3 . C01S02.005: The slope of L is (3 ( 3)) / (5 2) = 2, so an equation of L is y 3=2( x 5); that is, y =2 x 7 . C01S02.006: An equation of L is y ( 4) = 1 2 ( x ( 1)); that is, 2 y +7= x. C01S02.007: The slope of L is tan(135 )= 1, so L has equation y 2= 1 · ( x 4); that is, x + y =6 . C01S02.008:
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This note was uploaded on 09/14/2011 for the course MATH 101 taught by Professor Cheng during the Spring '11 term at Ecole Hôtelière de Lausanne.

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