13_Cal_Solution of Calculus_6e

# 13_Cal_Solution of Calculus_6e - C01S02.017: y = ( x − 3)...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: C01S02.017: y = ( x − 3) 2 : Opens upward, vertex at (3 , 0). C01S02.018: y − 16 = − x 2 : Opens downward, vertex at (0 , 16). C01S02.019: y − 3 = ( x + 1) 2 : Opens upward, vertex at ( − 1 , 3). C01S02.020: 2 y = x 2 − 4 x + 4 + 4: y − 2 = 1 2 ( x − 2) 2 . Opens upward, vertex at (2 , 2). C01S02.021: y = 5( x 2 + 4 x + 4) + 3 = 5( x + 2) 2 + 3: Opens upward, vertex at ( − 2 , 3). C01S02.022: y = − ( x 2 − x ) = − ( x 2 − x + 1 4 ) + 1 4 : y − 1 4 = − ( x − 1 2 ) 2 . Opens downward, vertex at ( 1 2 , 1 4 ). C01S02.023: x 2 − 6 x + 9 + y 2 + 8 y + 16 = 25: ( x − 3) 2 + ( y + 4) 2 = 5 5 . Circle, center (3 , − 4), radius 5. C01S02.024: ( x − 1) 2 + ( y + 1) 2 = 0: The graph consists of the single point (1 , − 1). C01S02.025: ( x + 1) 2 + ( y + 3) 2 = − 10: There are no points on the graph. C01S02.026: x 2 + y 2 − x + 3 y + 2 . 5 = 0: x 2 − x + 0 . 25 + y 2 + 3 y + 2 . 25 = 0: ( x − . 5) 2 + ( y + 1 . 5) 2 = 0....
View Full Document

## This note was uploaded on 09/14/2011 for the course MATH 101 taught by Professor Cheng during the Spring '11 term at Ecole Hôtelière de Lausanne.

Ask a homework question - tutors are online