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Unformatted text preview: 6 2 ! 4!. Problem 2. This is question is just like Problem 66 in HW2. If all members of the Senior committee must be older than all members of the Junior committee, then choosing the two committees is the same as choosing one group of 25 + 20 = 45 people and then dividing them into the youngest 20 and oldest 25. So the answer is 100 45 ! 1...
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This note was uploaded on 09/15/2011 for the course AMAT 344 taught by Professor Raghaven during the Spring '11 term at SUNY Albany.
 Spring '11
 Raghaven

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