# HW8 - HW8 Solutions Dilip Raghavan 1 Section 7.2 Problem 4...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: HW8 Solutions Dilip Raghavan November 10, 2008 1 Section 7.2 Problem 4. Consider the amount of money given away in the tournament before the last round. This consists of two subtournaments with n 2 players each. So 2 a n 2 is given away prior to the last round. Now the subtournament won by the winner of the last round is just the whole tournament, which has n players. But we have already accounted for n 2 of them so far (as part of one of the two subtournaments prior to the final). So the winner of the last round gets 100 n 2 in the last round. So a n = 2 a n 2 + 100 n 2 = 2 a n 2 + 50 n , with the intial condition a 2 = 300 (if there are just 2 players, the winner gets 200 and the looser gets 100). By the table on page 292, the solution has the form a n = 50 n (log 2 n + A ). Problem 5. To merge 2 ordered k tuples into an ordered 2 k tuple requires 2 k- 1 comparisons. So given a set of size n (where n is some power of 2), divide it into two sets of size n 2 each. Now sorting each half requires a n 2 comparisons. So a total of 2 a n 2 comparisons. Now, we have 2 ordered n 2 tuples which we would like to merge. This needs n- 1 comparisons. So1 comparisons....
View Full Document

## This note was uploaded on 09/15/2011 for the course AMAT 356 taught by Professor Hernandez/rag during the Spring '11 term at SUNY Albany.

### Page1 / 2

HW8 - HW8 Solutions Dilip Raghavan 1 Section 7.2 Problem 4...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online