{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Fuel Cell Post-Lab

# Fuel Cell Post-Lab - Sutherland 1 Fuel Cell Lab Sutherland...

This preview shows pages 1–3. Sign up to view the full content.

Sutherland 1 October 23, 2006 Fuel Cell Lab Sutherland, James Christopher 1. 2. Given: Find: Watts for each level of resistance and generate the PEMFC power curve. Relationships: Power = Voltage * Current Solutions: Open Ω Power = 0.80 V * 0 A = 0 Watts 200 Ω Power = 0.74 V * 0.003 A = 0.0022 Watts 100 Ω Power = 0.71 V * 0.006 A = 0.0043 Watts 50 Ω Power = 0.68 V * 0.013 A = 0.0088 Watts 10 Ω Power = 0.59 V * 0.057 A = 0.0336 Watts 5 Ω Power = 0.54 V * 0.101 A = 0.0545 Watts 3 Ω Power = 0.49 V * 0.158 A = 0.0774 Watts 1 Ω Power = 0.40 V * 0.309 A = 0.1236 Watts Motor Ω Power = 0.71 V * 0.013 A = 0.0092 Watts

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Sutherland 2 3. Based on my calculations and data, high-current applications yielded more power, but the low-current was also accompanied by low resistance. 4. Using the data collected in the experiment and MATLAB graph of Current vs. Voltage, the Motor Ω resistance setting appears to be 100 Ω of resistance. Using Ohm’s Law (V = I R) however calculates the resistance to be: 0.71 V = 0.13 A * R R = 55 Ω This discrepancy is most likely due to human error in reading the measurements from the load box.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 3

Fuel Cell Post-Lab - Sutherland 1 Fuel Cell Lab Sutherland...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online