HW_4_sol - Solution Boundary conditions E t d = E t a D n d...

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Problem: An electric field inside a dielectric makes an angle of 25 o with the normal to an interface between the material and air. The relative permittivity of the dielectric is 1.8. What angle does the field make with the normal on the air side of the material?
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Unformatted text preview: Solution: Boundary conditions: E t d = E t a , D n d = D n a ( d is for the dielectric, a is for air) In air: tan q a = E t a E n a » E t a D n a = E t d D n d = 1 1.8 E t d E n d = tan 25 × 1.8 θ a = tan- 1 tan 25 o 1.8 ( ) » 14.5 o...
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This note was uploaded on 09/19/2011 for the course PHYS 4d taught by Professor Staff during the Winter '08 term at UCSD.

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