HW_4_sol

HW_4_sol - Solution Boundary conditions E t d = E t a D n d...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Problem: An electric field inside a dielectric makes an angle of 25 o with the normal to an interface between the material and air. The relative permittivity of the dielectric is 1.8. What angle does the field make with the normal on the air side of the material?
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Solution: Boundary conditions: E t d = E t a , D n d = D n a ( d is for the dielectric, a is for air) In air: tan q a = E t a E n a » E t a D n a = E t d D n d = 1 1.8 E t d E n d = tan 25 × 1.8 θ a = tan- 1 tan 25 o 1.8 ( ) » 14.5 o...
View Full Document

This note was uploaded on 09/19/2011 for the course PHYS 4d taught by Professor Staff during the Winter '08 term at UCSD.

Ask a homework question - tutors are online