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Unformatted text preview: I max = 35 μA . (b) the value of V ; Solution: ω = 2 πf = 4 . 78 × 10 2 rad/s 1 I = dQ dt = C dV dt =CωV sin ωt, I max = CωV ,C = ε A d . ⇒ V = I max Cω = I max d ωε A = 6 . 75 × 10 3 V (c) the maximum value of d Φ E /dt between plates. Solution: I D = ε d Φ E dt ⇒ ( d Φ E dt ) max = I max ε = 3 . 95 × 10 6 V · m/s. Bonus Problem A 1500nF capacitor with circular parallel plates 2 cm in diameter is accumulating charge at the rate 38 mC/s at some instant in time. (a) What will be the induced magnetic ﬁeld strength 10 cm radially outward from the center of the plates? Solution: B (2 πr ) = μ I. B = μ I 2 πr = 7 . 6 × 108 T (b) What will be the value of the ﬁeld strength after the capacitor is fully charged? Solution: Since I = 0 , B = 0 . 2...
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 Winter '08
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 Physics, Light, Frequency, Hertz, Wavelength, IMAX

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