problem02_52 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.52: a) ms 3 . 1 for 0 Slope = = t a b) graph under Area max t v h - = Rectangle Triangle A A + ) s cm 133 )( ms 3 . 1 ms 5 . 2 ( s cm 133 ) ms 3 . 1 ( 2 1 - + cm 25 . 0 c) a = slope of v– t graph 2 5 s cm 10 0 . 1 ms 3 . 1 s cm 133 ) ms 0 . 1 ( ) ms 5 . 0 ( × = a a zero. is slope the because 0 ) ms 5 . 1 ( = a d) h = area under v– t graph cm 10 0 . 5 ) s cm 100 )( ms 0 . 1 ( 2 1 ) ms 0 . 1 ( cm 10 3 . 8 s cm 33 ) ms 5 . 0 ( 2 1 ) ms 5 . 0 ( 2 Triangle 3 Triangle - - × = =
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Unformatted text preview: × = = ≈ A h A h cm 0.11 ) 33 . 1 )( ms 2 . ( s cm 133 ) ms 3 . 1 ( 2 1 ) ms 5 . 1 ( Rectangle Triangle = + = + ≈ A A h...
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