Physical Chem Notes-Practice 22

# Physical Chem Notes-Practice 22 - and Δ E = 1.12 × 10-20...

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22 Exercises to prepare for Feedback #6 A) For an electron (m= 9.1 × 10 -34 kg) in a box with L 1 = 10 nm, L 2 = 20 nm, and L 3 = 30 nm: What is the energy of the lowest energy state? What is the energy difference Δ E between the (1, 2, 3) state and the (3, 2, 1) state? Which state is higher in energy? What are the frequency and wavelength of the photon absorbed or emitted in exciting the electron between the two states? What state is degenerate with the (4, 2, 3) state? B) Calculate the reduced mass of 19 F 35 Cl The numbers refer to the Exercises (not Problems) in Physical Chemistry , 8 th Edition , by Peter Atkins and Julio De Paula. Numerical answers for the (b) exercises these are available in the back of the textbook, and more complete answers are in the Student Solutions Manual. 9.1 9.5 9.7 9.8 -10 9.15 Also, what is the vibrational frequency, ν , of Cl 2 , and the energy separation of adjacent energy levels? Problem 9.2 Answer to 9.15 ν = 1.7 × 10 13 sec -1
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Unformatted text preview: and Δ E = 1.12 × 10-20 Joules The numbers refer to the Exercises (not Problems) in Physical Chemistry , 9 th Edition , by Peter Atkins and Julio De Paula. Numerical answers for the (a) exercises these are available in the back of the textbook, and more complete answers are in the Student Solutions Manual. 8.1 8.6 -7 8.9-11 8.17 Also, what is the vibrational frequency, ν , of N 2 , and the energy separation of adjacent energy levels? Problem 8.2 Answer to 8.17 ν = 7.1 × 10 13 sec-1 and Δ E = 4.68 × 10-20 Joules Answers A) E (1, 1, 1) = (1 + 1/4 + 1/9) h 2 / (8mL 1 2 ) = 8.21 × 10-22 Joules Δ E = [ (9 + 4/4 + 1/9) – (1 + 4/4 + 9/9) ] h 2 / (8mL 1 2 ) = 4.28 × 10-21 Joules The (3, 2, 1) state is higher in energy ν = Δ E /h = 6.45 × 10 12 sec-1 and λ = 4.64 × 10-5 meters (46.5 μ m) The (1, 8, 3) state B) μ = m F × m Cl /(m F + m Cl ) = .019 × .035 / (.019+.035) / (6.022 × 10 23 ) = 2.04 × 10-26 kg...
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## This note was uploaded on 09/20/2011 for the course CHM 4411 taught by Professor Ohrn during the Spring '08 term at University of Florida.

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