329sum09hw2sol - ECE-329 Summer 2009 Homework 2 Solution 1...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
ECE-329 Summer 2009 Homework 2 — Solution June 17, 2009 1. Infinite charge sheets. a) Displacement vector at the origin due to sheet 1 ( ρ s 1 = 1 C m 2 ) D 1 = 1 2 ρ s 1 ˆ x = 1 2 ˆ x C m 2 . Displacement vector at the origin due to sheet 2 ( ρ s 2 = 1 C m 2 ) D 2 = - 1 2 ρ s 2 ˆ x = - 1 2 ˆ x C m 2 . Resultant displacement vector due to both sheets D = D 1 + D 2 = 0 C m 2 . b) Displacement vector at the origin due to sheet 1 ( ρ s 1 = 1 C m 2 ) D 1 = 1 2 ρ s 1 ˆ x = 1 2 ˆ x C m 2 . Displacement vector at the origin due to sheet 2 ( ρ s 2 = - 2 C m 2 ) D 2 = - 1 2 ρ s 2 ˆ x = 1ˆ x C m 2 . Resultant displacement vector due to both sheets D = D 1 + D 2 = 3 2 ˆ x C m 2 . 2. Let us apply Gauss law (in integral form) ˛ S E · d S = 1 o ˆ V ρdV to compute the electric flux ¸ S E · d S over the surface of a cube of volume V = L 3 that is centered at the origin. 1
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
ECE-329 Summer 2009 L 2 (1 , 1 , 1) L 2 ( - 1 , 1 , 1) L 2 ( - 1 , 1 , - 1) L 2 (1 , 1 , - 1) L 2 (1 , - 1 , - 1) L 2 (1 , - 1 , 1) L 2 ( - 1 , - 1 , 1) L 2 ( - 1 , - 1 , - 1) x y z dS 2 dS 1 dS 3 a) If the electric charge density within the cube is ρ = 1 C / m 3
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern