329sum09hw2sol - ECE-329 Summer 2009 Homework 2 Solution...

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Unformatted text preview: ECE-329 Summer 2009 Homework 2 Solution June 17, 2009 1. Infinite charge sheets. a) Displacement vector at the origin due to sheet 1 ( s 1 = 1 C m 2 ) D 1 = 1 2 s 1 x = 1 2 x C m 2 . Displacement vector at the origin due to sheet 2 ( s 2 = 1 C m 2 ) D 2 =- 1 2 s 2 x =- 1 2 x C m 2 . Resultant displacement vector due to both sheets D = D 1 + D 2 = C m 2 . b) Displacement vector at the origin due to sheet 1 ( s 1 = 1 C m 2 ) D 1 = 1 2 s 1 x = 1 2 x C m 2 . Displacement vector at the origin due to sheet 2 ( s 2 =- 2 C m 2 ) D 2 =- 1 2 s 2 x = 1 x C m 2 . Resultant displacement vector due to both sheets D = D 1 + D 2 = 3 2 x C m 2 . 2. Let us apply Gauss law (in integral form) S E d S = 1 o V dV to compute the electric flux S E d S over the surface of a cube of volume V = L 3 that is centered at the origin. 1 ECE-329 Summer 2009 L 2 (1 , 1 , 1) L 2 (- 1 , 1 , 1) L 2 (- 1 , 1 ,- 1) L 2 (1 , 1 ,- 1) L 2 (1 ,- 1 ,- 1) L 2 (1...
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329sum09hw2sol - ECE-329 Summer 2009 Homework 2 Solution...

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