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Unformatted text preview: ECE329 Summer 2009 Homework 2 — Solution June 17, 2009 1. Infinite charge sheets. a) Displacement vector at the origin due to sheet 1 ( ρ s 1 = 1 C m 2 ) D 1 = 1 2 ρ s 1 ˆ x = 1 2 ˆ x C m 2 . Displacement vector at the origin due to sheet 2 ( ρ s 2 = 1 C m 2 ) D 2 = 1 2 ρ s 2 ˆ x = 1 2 ˆ x C m 2 . Resultant displacement vector due to both sheets D = D 1 + D 2 = C m 2 . b) Displacement vector at the origin due to sheet 1 ( ρ s 1 = 1 C m 2 ) D 1 = 1 2 ρ s 1 ˆ x = 1 2 ˆ x C m 2 . Displacement vector at the origin due to sheet 2 ( ρ s 2 = 2 C m 2 ) D 2 = 1 2 ρ s 2 ˆ x = 1ˆ x C m 2 . Resultant displacement vector due to both sheets D = D 1 + D 2 = 3 2 ˆ x C m 2 . 2. Let us apply Gauss law (in integral form) ˛ S E · d S = 1 o ˆ V ρdV to compute the electric flux ¸ S E · d S over the surface of a cube of volume V = L 3 that is centered at the origin. 1 ECE329 Summer 2009 L 2 (1 , 1 , 1) L 2 ( 1 , 1 , 1) L 2 ( 1 , 1 , 1) L 2 (1 , 1 , 1) L 2 (1 , 1 , 1) L 2 (1...
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This note was uploaded on 09/16/2011 for the course ECE 329 taught by Professor Kim during the Fall '08 term at University of Illinois, Urbana Champaign.
 Fall '08
 Kim
 Electromagnet

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