problem02_44 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

  • Homework Help
  • PresidentHackerCaribou10582
  • 1

Info icon This preview shows page 1. Sign up to view the full content.

2.44: a) Using a y = –g, v 0 y = 5.00 s m and y 0 = 40.0 m in Eqs. (2.8) and (2.12) gives i) at t = 0.250 s, y = (40.0 m) + (5.00 s m )(0.250 s) – (1/2)(9.80 2 s m )(0.250 s) 2 = 40.9 m, v y = (5.00 s m ) – (9.80 2 s m )(0.250 s) = 2.55 s m and ii) at t = 1.00 s, y = (40.0 m) + (5.00 m/s)(1.00 s) – (1/2)(9.80 m/s 2 )(1.00 s) 2 = 40.1 m, v y = (5.00 s m ) – (9.80 2 s m )(1.00 s) = – 4.80 s m . b) Using the result derived in Example 2.8, the time is t = ) s m 80 . 9 ( ) m 0 . 40 0 )( s m 80 . 9 ( 2 ) s m 00 . 5 ( ) s m 00
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ( 2 2 2--+ = 3.41 s. c) Either using the above time in Eq. (2.8) or avoiding the intermediate calculation by using Eq. (2.13), , s m 809 ) m . 40 )( s m 80 . 9 ( 2 ) s m 00 . 5 ( ) ( 2 2 2 2 2 2 2 =--=--= y y g v v y y v y = 28.4 s m . d) Using v y = 0 in Eq. (2.13) gives . m 2 . 41 m . 40 ) s m 80 . 9 ( 2 ) s m 00 . 5 ( 2 2 2 2 = + = + = y g v y e)...
View Full Document

  • '
  • NoProfessor
  • Trigraph, The Time, Eq., intermediate calculation

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern