Organic 2 Review Problem 341

Organic 2 Review Problem 341 - REACTIONS AND IDENTIFICATION...

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Unformatted text preview: REACTIONS AND IDENTIFICATION 325 drop. !Note that the white precipitate of silver salts turns black (showing the presence of silver cyanide). Now add an excess of mercurous nitrate: the black precipitate redis- solves, but the silver halide remains undissolved. To determine which halogen is present, take 1-2 ml. of the filtrate from the sodium fusion, and add dilute sulphuric acid until just acid to litmus. Add about i ml. of benzene and then about i ml. of chlorine water and shake. A yellowish-brown colour in the benzene indicates bromine, and a violet colour iodine. If neither colour appears, the halogen is chlorine. The result may be confirmed by testing the solubility of the silver halide (free from cyanide) in dilute ammonia solution: silver chloride is readily soluble, whereas the bromide dissolves with difficulty, and the iodide not at all. Sulphur. THE LASSAIGNE SODIUM TEST. The sodium fusion will have converted any sulphur present in the original compounds to sodium sulphide. Dissolve a few crystalsoriginal compounds to sodium sulphide....
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This note was uploaded on 09/19/2011 for the course CHM 2211 taught by Professor Castalleano during the Fall '06 term at University of Florida.

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