Introductionexp8

Introductionexp8 - I n troduction T he copper in a penny...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Introduction The copper in a penny goes through an oxidation-reduction when it is mixed with a solution that contains a higher reactivity then the copper in a penny does. Cu needs to placed in a solution higher then Zn would need to be placed in because Cu is less reactive so it needs a solution with a stronger oxidizing agent then H + . A solution like nitric acid would dissolve the Cu because it is a strong oxidizing agent. When the Cu and Zn are placed into the nitric acid nitrogen dioxide (NO 2 ) is given off from the reaction. During this reaction the oxidation of the Cu is taking place. The complex ion that is produced during the reaction is the Cu(H 2 O) 4 2+ ion and Zn(H 2 O) 4 2+ ion. The central atom is bonded to ligands (atoms that have unbonded pairs which allow them to bond to the central atom). The complex atoms that are formed are then added together with NH 3 to create two different complex atoms of Cu(NH 3 ) 4 2+ and Zn(NH 3 ) 4 2+ . The new Cu complex atom is dark blue in color and the Zn
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

Introductionexp8 - I n troduction T he copper in a penny...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online